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ÁöÇý Ű¿ì´Â ¿µ¾î(Á¦ 03 ȸ) : ÆÐƼÀÇ ³ªÀÌ

LV47 alexÇÒ¹è

2026-03-15 ¿ÀÈÄ 11:33:28 | Á¶È¸ : 302


ÁöÇý Ű¿ì´Â ¿µ¾î(Á¦ 03 ȸ) : ÆÐƼÀÇ ³ªÀÌ

--

[¹®] :

10 ³â Àü¿£, ÆÐƼ(patty)ÀÇ ¾î¸Ó´Ï´Â ÆÐƼÀÇ ³ªÀÌ¿¡ ´Ù¼¸ ¹è¿´´Ù.

ten years ago, pattys mother was five times pattys age.


Áö±ÝÀº ±×³à´Â ±×³à ¾î¸Ó´ÏÀÇ ³ªÀÌ¿¡ 3/7 ÀÌ µÇ°í,

5 ³â ÈÄ¿£ ±×³à´Â ¾î¸Ó´Ï ³ªÀÌÀÇ Àý¹ÝÀÌ µÉ °ÍÀÌ´Ù.

now she is three sevenths of her mothers age,

and in five years she will be half her mothers age.


±×³à(patty)°¡ ¸î »ìÀÌ µÇ¸é ±×³àÀÇ ¾î¸Ó´ÏÀÇ Àý¹ÝÀÌ µÉ±î?

how old will she be when she is half her mothers age?


º¸±â :

°¡) 15 »ì ³ª) 18 " ´Ù) 20 " ¶ó) 22 "

 

[´ä] ( )

==

<Áß¿ä ´Ü¾î>

time /taim/[ŸÀÓ]

n. ½Ã°£, ¶§, Àá½Ã, ±âȸ, Â÷·Ê(turn), ½Ã´ë, (¸î) ¹ø, ȸ, ¹è, °ö.

ten ¡­s a day / ÇÏ·ç¿¡ 10 ȸ.

==

[Á¤´ä ¹× ÇØ¼³]

Á¤´ä : ´Ù) 20 (ÇöÀç patty=15, mom=35)


ÇØ¼³ :

ÇöÀç patty¿Í ¾ö¸¶ÀÇ ³ªÀ̸¦ p¿Í mÀ¸·Î ÇÏÀÚ.

1) 10³â Àü -- (p-10)5 = m-10

2) Áö±Ý -- p=3/7m,

3) 5³â ÈÄ --

p+5=(m+5)1/2, p=(m+5)1/2-5, p=0.5m+2.5-5, p=0.5m-2.5

0.5m-2.5=3/7m, -->0.5m-3/7m=2.5, --> m=35, ¡Å p=15


°Ë»ê : m=35¸¦

2)¿¡ ´ëÀÔÇϸé p=15

1)¿¡ ´ëÀÔÇϸé (p-10)5=m(35)-10, -->5p -50=35-10, 5p=75,

¡Å p=15

==

==

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